Abstract
In this paper, we prove a Stolarsky type inequality for fuzzy integrals. More precisely, we show that:{cauchy integral}01 f fenced(xfrac(1, a + b)) d μ ≥ fenced({cauchy integral}01 f fenced(xfrac(1, a)) d μ) fenced({cauchy integral}01 f fenced(xfrac(1, b)) d μ),where a, b > 0, f : [0, 1] → [0, 1] is a continuous and strictly monotone function and μ is the Lebesgue measure on R.
| Original language | English |
|---|---|
| Pages (from-to) | 55-59 |
| Number of pages | 5 |
| Journal | Applied Mathematics and Computation |
| Volume | 196 |
| Issue number | 1 |
| DOIs | |
| State | Published - 15 Feb 2008 |
Keywords
- Fuzzy measure
- Monotone functions
- Sugeno integral
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